(x+7)(x-3)=x^2+1

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Solution for (x+7)(x-3)=x^2+1 equation:


Simplifying
(x + 7)(x + -3) = x2 + 1

Reorder the terms:
(7 + x)(x + -3) = x2 + 1

Reorder the terms:
(7 + x)(-3 + x) = x2 + 1

Multiply (7 + x) * (-3 + x)
(7(-3 + x) + x(-3 + x)) = x2 + 1
((-3 * 7 + x * 7) + x(-3 + x)) = x2 + 1
((-21 + 7x) + x(-3 + x)) = x2 + 1
(-21 + 7x + (-3 * x + x * x)) = x2 + 1
(-21 + 7x + (-3x + x2)) = x2 + 1

Combine like terms: 7x + -3x = 4x
(-21 + 4x + x2) = x2 + 1

Reorder the terms:
-21 + 4x + x2 = 1 + x2

Add '-1x2' to each side of the equation.
-21 + 4x + x2 + -1x2 = 1 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-21 + 4x + 0 = 1 + x2 + -1x2
-21 + 4x = 1 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-21 + 4x = 1 + 0
-21 + 4x = 1

Solving
-21 + 4x = 1

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '21' to each side of the equation.
-21 + 21 + 4x = 1 + 21

Combine like terms: -21 + 21 = 0
0 + 4x = 1 + 21
4x = 1 + 21

Combine like terms: 1 + 21 = 22
4x = 22

Divide each side by '4'.
x = 5.5

Simplifying
x = 5.5

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